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1171L-ONLY | Rotational Dynamics with Moment of Inertia & Angular Momentum

Background

● Background Overview

The motion of an object can be divided into two, completely independent parts: the linear (translational) motion of the center of mass and the rotational motion of the object around an axis through the center of mass. The linear motion is explained by Newton’s 2nd Law of motion: a net force FnetF_{net} acting on an object of mass mm will cause the object to experience a linear acceleration aa given by

Fnet=maF_{net} = m a

Rotational motion can be described in a very similar manner, but the quantities involved need to be changed to rotational quantities. These quantities are described and explained in detail in the following paragraphs.

● Moment of Inertia

In rotational motion the moment of inertia (usually denoted by II) takes the role of mass. An object with a large value of II will be reluctant to change its rotational motion. Just as mass this quantity is a scalar, meaning that it has no direction. The moment of inertia of a system of objects can be determined easily by adding the moment of inertia of each of the different components making up the entire system. The moment of inertia depends not only on the mass of the object but also on how the mass is distributed with respect to the axis of rotation. The further the mass is away from the axis of rotation, the higher the moment of inertia will be. For a point mass (an object that can be considered small with respect to its distance from the axis of rotation) the moment of inertia is defined as

I=mR2I = m\, R^{2}

where mm is the mass of the object and RR is the distance of the object from the axis of rotation.

The calculation of the moment of inertia for more complex objects is a rather straightforward process, but can be very tedious. In most cases simple expressions can be found to calculate the value of II. The list below gives the moment of inertia for a few objects used in this lab:

IallPointMasses=i=1NIi=i=1NMiRi2I_\text{allPointMasses} = \sum_{i=1}^N I_i = \sum_{i=1}^N M_i\,R_i^{2}
I=112MrodLrod2I= \frac{1}{12} M_{rod} \, L_{rod}^{2}
I=12MDRD2I= \frac{1}{2} M_{D} \, R_{D}^{2}
I=MRRR2I= M_{R} \, R_{R}^{2}
I=12MR(Ri2+Ro2)I=\frac{1}{2} M_{R} \, \left(R_{i}^2 + R_{o}^2\right)

● Torque

A force by itself is not enough to determine whether an object will start to rotate (just think about how a force that is applied to the hinges of a door will not rotate the door). Instead we define a new quantity, called torque τ\tau, which combines the force and the distance from the axis of rotation (also called the lever arm). This quantity is a vector quantity, meaning that it does have a direction

τ=F×d.\vec{\tau} = \vec{F}_{\perp} \times \vec{d}.

Here d\vec{d} denotes the lever arm (directed outward from the center) and F\vec{F}_{\perp} is the component of the force perpendicular to the lever arm.

● Newton’s 2nd Law for Rotational Motion

With the above definitions we can now formulate a rotational version of Newton’s 2nd Law. An object with moment of inertia II will experience an angular acceleration α\vec{\alpha}, if a net torque τnet\vec{\tau}_{\text{net}} acts on it

τnet=Iα.\vec{\tau}_{\text{net}} = I \vec{\alpha}.

● Calculating the Moment of Inertia

One can use Newton’s 2nd Law for Rotational Motion to calculate the moment of inertia of an object from the angular acceleration α\alpha and the net torque acting on the object.

I=τnetαI = \frac{\left|\vec{\tau}_{\text{net}}\right|}{\left|\vec{\alpha}\right|}

The simplified sketch in Figure 1 shows the setup used in this lab. The net torque acting on the pulley can be written as

τnet=TRP|\vec{\tau}_{\text{net}}| = T \, R_{P}

where TT is the tension in the string and RPR_{P} is the radius of the 3-step pulley. Since the tension is not known it has to be determined from the linear acceleration a of the hanging mass, using the net force acting on the mass mhangerm_\text{hanger} (see force diagram in the sketch):

Fnet=mhangergT=mhangera.F_{\text{net}} = m_\text{hanger} g - T = m_\text{hanger} a.

In addition the linear acceleration aa is related to the angular acceleration α\alpha by

a=αRP.a = \alpha R_{P}.

Using this set of equations one can now solve for the moment of inertia, II,

I=mhanger(gRPαRP2)α.I = \frac{m_\text{hanger} \left(g R_{P} - \alpha R_{P}^2\right)}{\alpha}.
Left: Sketch of a pulley of mass M and radius R being accelerated by a hanging mass m_\text{hanger}. Note that the pulley in the lab is actually horizontal, but is drawn vertically here for simplicity. Right: Force diagram for the hanging mass m_\text{hanger}.

Figure 1:Left: Sketch of a pulley of mass MM and radius RR being accelerated by a hanging mass mhangerm_\text{hanger}. Note that the pulley in the lab is actually horizontal, but is drawn vertically here for simplicity. Right: Force diagram for the hanging mass mhangerm_\text{hanger}.

● Angular Momentum

A similar derivation as above can be used to define the quantity of angular momentum L\vec{L} from the definition of linear momentum (p=mv\vec{p} = m \vec{v})

L=Iω|L| = I \omega

Angular momentum is conserved (meaning it will not change its value) if there is no external torque acting on a system

Li=Lf.\vec{L}_i = {L}_f.

This can be used to determine the angular velocity of a system if the moment of inertia changes

Iiωi=Ifωf.I_i \omega_i = I_f \omega_f.

THE PARALLEL AXIS THEOREM is used to calculate the moment of inertia of an object of mass MM rotating about a rotation axis that does not pass through the center of mass (e.g. the ring on top of the apparatus is off center). The moment of inertia for the axis Iaxis{I_{axis}} is

Iaxis=Iring+Mdcm2{I_{axis}} = {I_{ring}} + M d_{cm}^2

where Icm{I_{cm}} is the moment of inertia about an axis through the center of mass parallel to the rotation axis. The distance between the parallel axes is dcm{d_{cm}}. In the Conservation of Angular Momentum experiment you drop the ring on the rotating apparatus. Although you try to drop the ring centered on the axis of rotation, it often lands off center. You will run a case where you try to center it, and then another case where you purposefully drop it off center.

Experimental Procedure

● Preliminary Setup

The lab today makes use of a rotary sensor, which is able to detect and measure angular displacement, angular velocity, and angular acceleration. This Rotary Motion Sensor (RMS), with a stated uncertainty of 0.09°, is attached to a vertical rod and has a 3-step pulley affixed to its axle (see Figure 2). Objects with different moments of inertia can be mounted onto the 3-step pulley and their rotational motion be measured. A second, black pulley (called a Super Pulley) is attached at an angle to the RMS to allow a string to spool off the 3-step pulley as shown in Figure 2. A weight hanger of known mass mhangerm_\text{hanger} is attached to the free end of the string and provides an accelerating torque to the 3-step pulley and therefore to the object mounted on it.

The objects to be mounted are either a rod with point masses in Figure 3 and a disk with an accompanying thick ring in Figure 4.

In this lab, you will run a Moment of Inertia experiment and an Angular Momentum experiment. You will first determine the angular acceleration from a graph of angular velocity vs. time using data recorded with the RMS. The data will be collected and analyzed in Capstone. The moment of inertia of both two point masses and a thick ring will be determined from those experimental angular acceleration values. Finally in the Angular Momentum experiment, you will verify the validity of angular momentum conservation in an inelastic collision, and consider the parallel axis theorem.

Rotary Motion Sensor (RMS) with 3-step pulley (transparent) and Super Pulley (black). Super pulley should be at an angle to ensure the thread lines up tangent to the 3-step pulley.

Figure 2:Rotary Motion Sensor (RMS) with 3-step pulley (transparent) and Super Pulley (black). Super pulley should be at an angle to ensure the thread lines up tangent to the 3-step pulley.

Sketch of the RMS apparatus setup for “point masses” on a rotating rod. Left) Just apparatus (i.e. rod), Right) total from the apparatus and point masses combined.

Figure 3:Sketch of the RMS apparatus setup for “point masses” on a rotating rod. Left) Just apparatus (i.e. rod), Right) total from the apparatus and point masses combined.

Experimental setup of the RMS apparatus with disk alone (left) and with disk and ring mounted (right). The setup varies slightly from the one used in the lab.

Figure 4:Experimental setup of the RMS apparatus with disk alone (left) and with disk and ring mounted (right). The setup varies slightly from the one used in the lab.

Experimental setup of the Conservation of Angular Momentum experiment with *collisions: Left) Thick ring dropped on-axis, Right) Thick ring dropped off-axis.

Figure 5:Experimental setup of the Conservation of Angular Momentum experiment with *collisions: Left) Thick ring dropped on-axis, Right) Thick ring dropped off-axis.

● Part Ia_\text{a} --- Moment of Inertia of Two Point Masses

● Part Ib_\text{b} --- Moment of Inertia of a Thick Ring

● Part II --- Conservation of Angular Momentum

  1. BEFORE CLOSING CAPSTONE:

  2. BEFORE LEAVING LAB:

Post-Lab Submission --- Interpretation of Results

This week’s lab is built of essentially two different, but still related to rotational motion, experiments. To assist in your analysis and writeups, the suggested talking points below are broken up into the Moment of Inertia and Angular Momentum parts of the lab. You will still have single document for error analysis and single document for results as assignments in Blackboard.

● Finalized Spreadsheets

● Moment of Inertia Post-Lab

● Angular Momentum Post-Lab

The Whiteboard