Skip to article frontmatterSkip to article content
Site not loading correctly?

This may be due to an incorrect BASE_URL configuration. See the MyST Documentation for reference.

Electrical Example of an Exponential Decay Process with Resistors & Capacitors (RC Circuits)

Background

● Background Overview

Many physical processes involve a rate of change that is proportional to the magnitude of the quantity itself; the result is an in exponential behavior over time. In this experiment, you will investigate the exponential relaxation (decay) of the voltage or charge on a capacitor.

An electrical analogy of this process is a simple circuit where a capacitor discharges through a resistor connected across its terminals. The schematic for this RC circuit is shown in Figure 1-right.

Left) Schematic of circuit charging the capacitor. Right) Schematic of RC circuit disconnected from the battery and discharging through the resistor.

Figure 1:Left) Schematic of circuit charging the capacitor. Right) Schematic of RC circuit disconnected from the battery and discharging through the resistor.

With the switch connecting the capacitor to the batteries (see Figure 1-left), the capacitor rapidly charges up to the potential of the batteries. Since a capacitor will not pass a DC current, a positive charge builds up on one of the plates while a negative charge forms on the other. When the switch is flipped to connect the capacitor to the resistor, we have the circuit (shown in Figure 1-right) containing a charged capacitor with a resistance across its terminals.

● Time Dependence of Voltage in a Resistor-Capacitor (RC) Circuit

We will now investigate how the voltage across the capacitor changes with time, starting at t=0t = 0 when the capacitor is fully charged. The voltage will be measured by the voltmeter VV connected as shown in Figure 1. As time progresses, current will flow from the positively charged plate of the capacitor through the resistance RR to the negatively charged plate.

Since a voltage exists across the capacitor, there must also be a voltage across RR. This implies an electric current, and from Ohm’s Law:

I=VRI=\frac{V}{R}

Since current is a flow of charge, QQ, and since the two sides of the capacitor are isolated from each other, the charge which flows through the resistor must originate on one of the plates and terminate on the other. Thus the flow of current reduces the charge on the capacitor. In a time, tt, the amount of charge that passes through the resistor is I×tI \times t. This must be Q-Q (the negative change in the charge on the capacitor) which leads to the relation:

I=dQdtI=-\frac{dQ}{dt}

The value of the resistance limits the amount of current that can flow and thus limits the rate of discharge of the capacitor.

From the definition of a capacitor, we know that the larger the voltage applied to the capacitor, the more charge it will put on the capacitor. Hence, if VV is the voltage across the capacitor, then QQ is proportional to VV. The larger the plate area, the more charge it should hold. In addition, if the plates are brought closer together, the positive plate will attract more negative charge from the battery to the negative plate. All these factors have to do with the geometry and construction details of the device. Thus, the bigger the plate area and the smaller the plate spacing, the larger the charge that accumulates in the capacitor for a given voltage. Hence we can write:

Q=CVQ=CV

where CC is a constant for a given capacitor called its capacitance.

Combining these three equations, we obtain:

dQdt=QRC\frac{{\rm d}Q}{{\rm d}t}=-\frac{Q}{RC}

Notice that the rate of change of the charge at any time is directly proportional to the amount of charge on the capacitor at that time. (This is similar to the amount of radiation given off by a quantity of decaying atoms.) By writing (4) in the form:

dQQ=dtRC\frac{{\rm d}Q}{Q}=-\frac{{\rm d}t}{RC}

both sides of the equation can be integrated to obtain:

ln(Q)=1RC+ln(Q0)\ln(Q)=\frac{1}{RC}+\ln(Q_{0})

After some simplification, the solution to this differential equation is:

Q=Q0etRCQ=Q_{0}e^{-\frac{t}{RC}}

At t=0t=0, V=V0V = V_{0}, so that Q=CV0Q = CV_{0} for t=0t = 0. Thus the behavior of QQ or VV is the same after the switch is opened:

Q=CVetRCV=V0etRCQ=CV e^{-\frac{t}{RC}} \rightarrow V=V_{0}e^{-\frac{t}{RC}}

The behavior of the current II is found directly from this:

I=dQdt=V0RetRCI=-\frac{dQ}{dt}=\frac{V_{0}}{R}e^{-\frac{t}{RC}}

The product RCRC has the units of time (Ω×F)(\Omega \times F); we can verify this by using dimensional analysis:

RCVI×QVQIQ×tQtRC\rightarrow \frac{V}{I}\times \frac{Q}{V}\rightarrow \frac{Q}{I}\rightarrow Q\times \frac{t}{Q}\rightarrow t
[RC]=Ω×FVC/s×CVC×sCs[RC]=\Omega \times F\rightarrow \frac{V}{C/s}\times \frac{C}{V}\rightarrow C\times \frac{s}{C}\rightarrow s

This product is called the time constant of the circuit. In a time equal to RCRC, the voltage, VV, drops to a fraction:

VV0=1e0.368\frac{V}{V_{0}}=\frac{1}{e} \approx 0.368

This means that in any interval of time equal to RCRC, the voltage has decreased to 36.8% of the initial value. In determining RCRC, it is often more convenient to measure the time for the voltage to drop to 12\frac{1}{2} of its initial value and from this to compute RCRC. The “half-life” t1/2t_{1/2} is given by:

V1/2V0=12=et1/2RC\frac{V_{1/2}}{V_{0}}=\frac{1}{2}=e^{-\frac{t_{1/2}}{RC}}

Taking the natural logarithm of both sides and simplifying we obtain:

t1/2=RCln20.693RCt_{1/2}=RC \ln 2 \simeq 0.693 RC

or

RC=1.443t1/2\boxed{ RC=1.443 t_{1/2} }

Note that by taking the natural log of the expression for the voltage, (8), we obtain:

lnV=lnV0tRC\ln V=\ln V_{0}-\frac{t}{RC}

in the form of y=mx+by=mx+b,

lnV=(1RC)t+lnV0\boxed{ \ln V=-(\frac{1}{RC})t+\ln V_{0} }

If we plot the value of the natural log of VV as a function of time, tt, we obtain a straight line whose slope is 1/RC-1/RC with an intercept of lnV0\ln V_{0}. From this slope, we can obtain a measured value for the product RCRC which is the time constant, i.e. the time it takes the voltage (or charge) to decay to 1/e1/e of its original value (see (12)).

● Dividing Charge across Capacitors in a Capacitor-Capacitor (CC) Circuit

A capacitor CC at voltage VV holds a charge Q=CVQ = CV. In the circuit shown in Figure 2 when the single-pole-double-throw (SPDT) switch connects the first capacitor (Cfirst-positionC_\text{first-position}) to the voltage source, it holds a charge Qfirst-position=Cfirst-positionVsourceQ_\text{first-position} = C_\text{first-position} V_\text{source}. The switch is then flipped to disconnect the first capacitor from the battery and connect it to the second capacitor (Csecond-positionC_\text{second-position}). Charge moves from the first-position capacitor to the second-position capacitor, lowering the voltage and sharing the charge. Assuming the second capacitor is initially uncharged, the total charge is unchanged. The total charge QQ must then be divided between the two capacitors so that they come to the same lower final voltage:

VfCfirst-position=Qfirst-positionVfCsecond-position=Qsecond-positionQfirst-position+Qsecond-position=Q=Cfirst-positionVsourceVf=Cfirst-positionCfirst-position+Csecond-positionVsource\begin{aligned} V_f C_\text{first-position} &= Q_\text{first-position} \\ V_f C_\text{second-position} &= Q_\text{second-position} \\ Q_\text{first-position}+Q_\text{second-position} &= Q = C_\text{first-position} V_\text{source} \\ V_f &= \frac{C_\text{first-position}}{C_\text{first-position}+C_\text{second-position}} V_\text{source} \end{aligned}

Because the two capacitors are at the same voltage, the total charge is divided between them in proportion to their capacitance.

Left) Schematic of circuit charging the capacitor. Right) Schematic of CC circuit disconnected from the battery and discharging to a separate capacitor.

Figure 2:Left) Schematic of circuit charging the capacitor. Right) Schematic of CC circuit disconnected from the battery and discharging to a separate capacitor.

● Equipment

The general setup with electrical schematic can be seen in Figure 3, with the voltmeter attached on either side of the capacitor section of the circuit. Capacitors to be experimentally determined, resistors to be treated as known constants, and wire and jumper bars are shown in Figure 4.

Table 1:Equipment

CategoryItems
Resistors• 2x ceramic/metal-film resistors: R1,brownR_{1\text{,brown}}, R2,blueR_{2\text{,blue}}
Capacitors• 2x capacitors: C1,bigC_{1\text{,big}}, C2,smallC_{2\text{,small}}
PASCO Modular Circuit Kit• 4x corner modules
• 1x T-junction module
• 1x straight-line module
• 2x AA battery modules
• 3x spring clip modules (attach resistors, capacitors, jumper bar)
• 1x SPDT switch module (change circuits to charge / discharge capacitors
• 13x U-shaped jumper clips
Measurement Device (“actual”)• Fluke multimeter with alligator clips (for “actual” values)
alt text: measure “actual” resistor values
alt text: measure “actual” capacitor values for later experimental comparison
Experimental Voltage Measurement• Capstone voltmeter (Connected across capacitors using alligator clips on jumper bars)
Left) Schematic, with circuit modules with spring modules for connecting capacitors, resistors, jumper bars. Right) Example of actual setup with voltmeter (used in Capstone) is connected across the eventual locations of the capacitor(s).

Figure 3:Left) Schematic, with circuit modules with spring modules for connecting capacitors, resistors, jumper bars. Right) Example of actual setup with voltmeter (used in Capstone) is connected across the eventual locations of the capacitor(s).

Example of capacitors, resistors, and wire and jumper bar to be used.

Figure 4:Example of capacitors, resistors, and wire and jumper bar to be used.

Demo Video: Setup & Procedure

Some clarifications, additions, or corrections since this video is slightly outdated:

Demonstration video. Reviews overall setup and procedure. *Yes audio*

If embedding is broken, follow: https://www.youtube.com/watch?v=qIOAo6_dHeY

Experimental Procedure

● Procedure Preview

● EXPERIMENT I --- Discharging Capacitor through Reistor (RC Circuit)

We study resistor-capacitor circuits and how capacitors discharge. Some ideas to think about as you go about this experiment is: How do different RC (resistor-capacitor) combinations affect the change of their circuits’ voltages over time? How do the two analysis methods (half-life and linear-fit) compare? How well does your average value of capacitance ±σ\pm\sigma agree with your “actual” (a.k.a. expected) values?

You will have two resistors (treated as constants) and two capacitors (all shown in Figure 4). From those, you will have five RC combination cases (shown in Table 2). The capacitor values will be determined by analyzing how the voltage across the capacitors change over time and analyzed with two different analysis methods.

Table 2:Resistor–Capacitor Combinations

CaseResistorCapacitor Configuration
1R1R_1 (brown)C1C_1 (BIG)
2R2R_2 (blue)C1C_1 (BIG)
3R1R_1 (brown)C2C_2 (small)
4R1R_1 (brown)(C1+C2)parallel(C_1+C_2)_{\text{parallel}}
5R1R_1 (brown)(C1+C2)series(C_1+C_2)_{\text{series}}

○ Exp. I --- Preliminary Setup

  1. Create a common data table for:

    • R1R_1: Resistor 1 (brown)

    • R2R_2: Resistor 2 (blue)

    • C1C_1: Capacitor 1 (BIGGER)

    • C2C_2: Capacitor 2 (smaller)

    • (C1+C2)parallel(C_1+C_2)_{\text{parallel}}: Capacitors in parallel (reminder of parallel vs. series in Figure 6)

    • (C1+C2)series(C_1+C_2)_{\text{series}}: Capacitors in series

  2. Measure and record:

    • “actual” resistance values with the Fluke multimeter set to measure resistance (Ω(\Omega or alt text, check units/range)

    • “actual” capacitance values of your capacitors (both single and in parallel and series) for comparisons to experimental data later; use the Fluke multimeter set to measure farads (use the yellow alternate function of the ohmmeter, alt text, check units/range).

  3. You can set aside the Fluke multimeter, as the rest of your data will come from Capstone.

  4. Prepare Capstone:

    • If not already connected, connect the voltmeter wires to the PASCO 850 Universal Interface via the Analog Input (Channel A) and on either side of where the capacitors will be inserted into the circuit’s spring modules (see Figure 3-right). Red/positive lead must be on the left, black/negative lead must be on the right due to polarity.

    • Open the Capstone file on the desktop for today. After it loads, and you confirm in the Hardware Setup side panel that the voltage sensor is configured/active (no warning triangles, otherwise double check the 850 interface is powered on).

    • Graphs/Data --- They should be already set up.

      • Top graph should be Voltage versus Time

      • Bottom graph should be Natural Log(V) vs. Time

      • Data table should show voltages and times (this table is connected to the V vs. T plot, so if you highlight data points on the plot, they’ll be highlighted in the table)

  5. Zero the voltage sensor and check sampling rate:

    • DO NOT ADD RESISTORS OR CAPACITORS TO THE CIRCUIT YET

    • Open the circuit by opening the single-pole-double-throw (SPDT) switch to ensure batteries are disconnected

    • In the recording bar, with the voltage sensor selected, alt text,

      • Set sample rate to 2500 samples per second

      • Press record and view V vs. T (top graph)

      • Click the zero button (zero with two yellow arrows pointing towards each other). Ensure voltage on V vs. T plot shows 0V0\text{V}.

○ Exp. I --- Data Acquisition

  1. Starting with the first case, connect the resistor, capacitor(s), switch, batteries, voltmeter as shown in Figure 5. Also see Figure 6 for the cases involving capacitors in parallel and series.

    Modular electronic RC circuit. The resistors and capacitors will just be placed in the spring modules to become part of the circuits. Left) Example with lower capacitor being charged by batteries in the bottom circuit. STAR Denotes switch position down. Right) Example with lower capacitor discharging through the resistor in the top circuit. STAR Denotes switch position up.

    Figure 5:Modular electronic RC circuit. The resistors and capacitors will just be placed in the spring modules to become part of the circuits. Left) Example with lower capacitor being charged by batteries in the bottom circuit. STAR Denotes switch position down. Right) Example with lower capacitor discharging through the resistor in the top circuit. STAR Denotes switch position up.

    Left) Parallel capacitors and Right) Series capacitors in spring modules.

    Figure 6:Left) Parallel capacitors and Right) Series capacitors in spring modules.

  2. Create a data table with TWO MAIN SECTIONS (half-life analysis method, linear-fit analysis method) for the first resistor and capacitor case (once you have this all set up, you’ll then be able to just copy and paste this data table for the other RC combinations):

    • With five columns (one for each of the 5 decay trials, the act of discharging a capacitor through resistor) --- trials are suggested to go horizontal on the spreadsheet today due to the many variables we will use within each case. Also include columns for the average values and for the standard deviation (σ\sigma) as needed. NOTE: For today, this σ\sigma is effectively an overestimation of your ± uncertainty range around the average.

    • Include a section for the Half-Life analysis method (t1/2)t_{1/2}):

      • VinitV_{\text{init}}: Initial voltage, right after decay starts

      • VfinalV_{\text{final}}: Final voltage, voltage that is half the value of the initial voltage, Vinit/2V_{\text{init}}/2

      • tinitt_{\text{init}}: Initial time, when V=VinitV=V_{\text{init}}. Found either with the multi-coordinates tool in the Capstone graphs, or in the Capstone data table.

      • tfinalt_{\text{final}}: Final time, when V=VfinalV=V_{\text{final}}. Found in a similar way in Capstone, just when voltage reaches half of its initial voltage.

      • t1/2t_{1/2}: Half-life, the duration it takes for initial quantity to halve (tfinaltinitt_{\text{final}}-t_{\text{init}}, characteristic of an exponential decay)

      • Chalf-life-methodC_{\text{half-life-method}}: Capacitance as determined by the rearrangement of (15)

    • Include another section for the linear-fit analysis method (LN(V) vs. Time):

      • Experimental slope: from the linear fit of the natural log(V) vs. time plot (linearizing the exponential decay) in Capstone where the fit will be in the form y=mt+by=mt + b

      • RCRC: Decay time constant of the exponential decay as determined from the slope

      • Clinear-fit-methodC_{\text{linear-fit-method}}: Capacitance as determined from the decay time constant found with the LN(V) vs. T plot

  3. DATA TAKING:

    • Start recording in Capstone. Confirm, with the SPDT switch not connected to either circuit and the capacitor discharged (use the red wire to connect either side of the capacitor to rapidly discharge it), that the voltage sensor is reading zero volts --- if not, double check the zeroeing procedure earlier.

    • Conduct 5 decay trials (can be done in the same Capstone recording):

      • Flip the SPDT switch DOWN to connect the batteries to the capacitor (Figure 5-left) and observe the voltage plot as the capacitor rapidly charges to VinitV_\text{init} (should be near 3V3\,\text{V} as can be seen in the top plots of Figure 7).

      • Once the capacitor is fully charged, flip the switch UP to connect the capacitor to the resistor (Figure 5-right); observe the decay of the voltage across the capacitor. In essence, the battery has been eliminated from the circuit and the capacitor is now acting as the voltage source.

        • Wait until the voltage drops to less than 10% ofVinit10\%~\text{of}\,V_\text{init} (e.g. if Vinit=3.0VV_\text{init}=3.0\,\text{V}, then V10-percent=0.3VV_\text{10-percent}= 0.3\,\text{V} as can be seen in the top plots of Figure 7).

    • Repeat four more times for a total of 5 decay trials within this single Capstone recording. You will analyze this whole data set in the following methods.

      Example Voltage vs. Time plot (top) and LN(V) vs. Time plot (bottom). Left) Time of start of a decay trial. Center) Time when half of the initial voltage is reached (i.e. after a half-life or t_1/2). Right) Time of the effective end of a decay trial when voltage drops to 10% of initial voltage (i.e. when V = V_\text{10-percent}.)

      Figure 7:Example Voltage vs. Time plot (top) and LN(V) vs. Time plot (bottom). Left) Time of start of a decay trial. Center) Time when half of the initial voltage is reached (i.e. after a half-life or t1/2t_1/2). Right) Time of the effective end of a decay trial when voltage drops to 10% of initial voltage (i.e. when V=V10-percentV = V_\text{10-percent}.)

○ Exp. I --- Data Analysis

  1. HALF-LIFE Analysis:

    • Determine the half-life, and from that determine the capacitance for each decay trial of the current case. Example of relevant locations are shown in Figure 7.

    • Find the initial voltage VinitV_\text{init} and time tinitt_\text{init} when your capacitor just starts to discharge (just after start of the decay, e.g. Figure 7-left). NOT when the capacitor is still connected to the battery.

    • Divide your initial voltage by 2 to calculate the final voltage VfinalV_\text{final} (i.e. when your quanity has decayed to half of its initial value)

    • Find and record the final time tfinalt_\text{final} for when your data reaches that final voltage (e.g. Figure 7-center).

    • Determine half-life from the time difference t1/2=tfinaltinitt_{1/2}= t_\text{final}-t_\text{init}.

    • From this and (15), determine your experimental capacitance, calculate the average capacitance and standard deviation of capacitance from the five trials.

  1. Linear-fit Analysis:

    • In the Capstone plot of LN(Voltage) vs. Time, we have effectively linearized the exponential function.

      • Highlight the data of the linear portion of the decay curve with the highlighter tool alt text. The linear section covers the time it took voltage to decay from 100% to 10% of the initial voltage (i.e. go from VinitV_\text{init} to V10-percentV_\text{10-percent}). You can use the multi-coordinates tool you used in the previous method to help you determine the temporal range (see example in Figure 8). If the fit does not display for the selected data, check the Curve Fit tool alt text is enabled.

      • Increase the fit’s coefficient sig. figs. to 4. (for reminder, see Figure 4).

    • Record the slope --- What does the slope represent; where did it come from? The natural log of the exponential function gives us a linear relationship between LN(Voltage) and Time, as described in (17). When plotted in Capstone, it should be in the form y=mt+by=mt + b.

    • Determine the time constant RCRC, the capacitance Clinear-fit-methodC_\text{linear-fit-method} from that time constant, and calculate the average capacitance and standard deviation of capacitance from the five trials. What does the RCRC represent?

      Example Voltage vs. Time plot (top) and LN(V) vs. Time plot (bottom). Left) Time of start of a decay trial. Lower bound of data-highlight box for fitting data in LN(V) vs. Time plot. Right) Time of the effective end of a decay trial when voltage drops to 10% of initial voltage (i.e. when V = V_\text{10-percent} and upper bound of data-highlight box.)

      Figure 8:Example Voltage vs. Time plot (top) and LN(V) vs. Time plot (bottom). Left) Time of start of a decay trial. Lower bound of data-highlight box for fitting data in LN(V) vs. Time plot. Right) Time of the effective end of a decay trial when voltage drops to 10% of initial voltage (i.e. when V=V10-percentV = V_\text{10-percent} and upper bound of data-highlight box.)

  2. PLOTS --- Take a screenshot or photo of one trial for each of your five cases of your VV vs. TT and LN(V) vs. T plots in Capstone. You should have 5 total sets of plots from the 5 cases. See example in Figure 8-right.

  1. For each case, compare your values for capacitance to the “actual” capacitance values of the capacitors, C1C_1, C2C_2, (C1+C2)parallel(C_1+C_2)_\text{parallel}, and (C1+C2)series(C_1+C_2)_\text{series} you measured with the multimeter in ○ Exp. I --- Preliminary Setup.

  2. Replace the resistor and/or capacitor for the next combination case and repeat the procedure (from ○ Exp. I --- Data Acquisition) above for each of the other cases listed in Table 2. Think about: How do different RC (resistor-capacitor) combinations affect the change of their circuits’ voltages over time (i.e. decay)?

● EXPERIMENT II --- Dividing Charge across Two Capacitors (CC Circuit)

Modular electronic circuit with two capacitors. Left) Example with lower capacitor being charged by batteries in the bottom circuit. STAR Denotes switch position down. Right) Example with lower capacitor discharging to the upper capacitor in the top circuit. STAR Denotes switch position up.

Figure 9:Modular electronic circuit with two capacitors. Left) Example with lower capacitor being charged by batteries in the bottom circuit. STAR Denotes switch position down. Right) Example with lower capacitor discharging to the upper capacitor in the top circuit. STAR Denotes switch position up.

○ Exp. II --- Preliminary Setup

  1. Consider C1C_{1} as high-capacitance and C2C_{2} as low-capacitance capacitors as you likely had done in the first experiment.

  2. Construct the circuit shown in Figure 9 by putting the lower-capacitance C2C_2 in the first position (bottom circuit when charged-by-batteries) and then replacing the resistor with the higher-capacitance C1C_1 in the second position (top circuit when charged by the first capactior). Ensure the voltmeter is still connected as before (either side of the first position) and continue using the same Voltage vs. Time plot in Capstone.

  3. Create a data table including:

    • Your experimentally-determined average capacitance values for C1C_1 and C2C_2 (remember to use Excel referencing)

    • Also include an area for the expected final voltage

    • Include three columns for initial and final voltages as well as the difference between the two. Create five rows for five trials.

    • Note: Initial voltage is VV when the battery is connected to CfirstC_\text{first} before you throw the switch to connect the capacitors together. Final voltage is VV after you throw the switch to connect CfirstC_\text{first} with CsecondC_\text{second} and allow the charge in the first capacitor to be distributed between the two capacitors.

  4. Temporarily connect the red wire across each capacitor to discharge them before flipping the switch (i.e. ensure the capacitors start with no charge stored and both circuits are open).

○ Exp. II --- Data Acquisition & Analysis

  1. Connect CfirstC_\text{first} to the battery using the single-pole-double-throw (SPDT) switch.

  2. Flip the SPDT switch to disconnect CfirstC_\text{first} from the battery and connect it to CsecondC_\text{second}. Flip the switch back and forth quickly for a total of five trials.

  3. From the VV vs. TT plot, record for each of the trials the initial voltage before charge is distributed and final voltage after the charge is distributed between the capacitors (notice the near immediate change). Examples are shown in Figure 10.

    Example Voltage vs. Time plot for experiment two.

    Figure 10:Example Voltage vs. Time plot for experiment two.

  4. PLOTS: Experiment II - Plot 1 --- Take a screenshot or photo that includes all five trais in one image of your VV vs. TT plot in Capstone.

  5. Calculate your expected final voltage using your initial voltage and the experimental C1C_1 and C2C_2 values with (18).

  6. Calculate the difference in voltage for each trial. Notice how the final voltage is drifting up towards the initial voltage and the difference between the two is changing. Something is wrong with the assumptions built into (18) (which should be true) which we used to. The problem is that after the first time throwing the switch, CsecondC_\text{second} is not at zero charge. So the total charge is higher than Qfirst=CfirstVQ_\text{first}=C_\text{first}V. Challenge: Can you figure out what the voltage will be after the second, third, or nnth time you flip the switch?

  7. Repeat the five trials in a new section of your spreadsheet, capacitors still in their current positions. But now, try temporarily connecting a wire across CsecondC_\text{second} to discharge it before flipping the switch for each trial. Record the initial and final voltages after doing this. Now you should consistently get the final voltage predicted by (18). Does this voltage difference agree with (18)?

  8. PLOTS: Experiment II - Plot 2 --- Take a similar screenshot or photo that includes all five trais in one image of your VV vs. TT plot in Capstone after using the wire to discharge the second capacitor between each flip.

  9. Instead of repeating this for the capacitors in swapped positions due to lab time constraints, discuss in the post lab what you would expect when the capacitors are swapped. <!--- from step 4 with the low- and high-capacitance capacitors in swapped positions in the circuit. --->

Post-Lab Submission --- Interpretation of Results

● Finalized Spreadsheets

● Post-lab Writeup

The Whiteboard

Overview 1st part.

Figure 11:Overview 1st part.

Overview 2nd part.

Figure 12:Overview 2nd part.

Multimeter settings; Capstone significant figures notes.

Figure 13:Multimeter settings; Capstone significant figures notes.